5-2500/x^2=0

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Solution for 5-2500/x^2=0 equation:



5-2500/x^2=0
Domain of the equation: x^2!=0
x^2!=0/
x^2!=√0
x!=0
x∈R
We multiply all the terms by the denominator
5*x^2-2500=0
We add all the numbers together, and all the variables
5x^2-2500=0
a = 5; b = 0; c = -2500;
Δ = b2-4ac
Δ = 02-4·5·(-2500)
Δ = 50000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{50000}=\sqrt{10000*5}=\sqrt{10000}*\sqrt{5}=100\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-100\sqrt{5}}{2*5}=\frac{0-100\sqrt{5}}{10} =-\frac{100\sqrt{5}}{10} =-10\sqrt{5} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+100\sqrt{5}}{2*5}=\frac{0+100\sqrt{5}}{10} =\frac{100\sqrt{5}}{10} =10\sqrt{5} $

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